Adsorption of a gas follows Freundlich adsorption isotherm. In the given plot, $x$ is the mass of the gas adsorbed on mass $m$ of the adsorbent at pressure $P . \dfrac{x}{m}$ is proportional to:

Question

Adsorption of a gas follows Freundlich adsorption isotherm. In the given plot, x is the mass of the gas adsorbed on mass m of the adsorbent at pressure P . (x)/(m) is proportional to:

Quantrex Academy · Accepted Answer

Correct answer: D. p ^ (1)/(2)

According to the Freundlich adsorption isotherm,

\dfrac{x}{m} = K{p}^{\dfrac{1}{n}}

Taking log on both sides.

\log \left(\dfrac{x}{m}\right) = logK + \dfrac{1}{n}log P

Slope from graph

= \dfrac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}} = \dfrac{2}{4} = \dfrac{1}{2}

or,

\dfrac{1}{n} = \dfrac{1}{2}

∴ \dfrac{x}{m} = K{p}^{\left(\dfrac{1}{2}\right)}

or

\dfrac{x}{m} ∝ {p}^{\left(\dfrac{1}{2}\right)}

Adsorption of a gas follows Freundlich adsorption isotherm. In the...

Options

Correct answer

Step-by-step solution

More from Surface Chemistry