If x gram of gas is adsorbed by m gram of adsorbent at pressure P the plot of x ~m versus P is linear. The slope of the plot is: ( m and k are constants and n>1 )

Correct answer: B. (1)/(n) According to Freundlich adsorption isotherm. aligned x m =kP^ 1 n & _ 10 x m = 1 n _ 10 P+ _ 10 k aligned This is the equation of straight line of type y=m x+c Hence slope is 1 / n(m) and intercept is _ e k .

JEE Main 201815 AprilEvening ShiftOnline

Exam: JEE Main
Year: 2018
Date: 15 April
Shift: Evening Shift
Mode: Online
Subject: Chemistry
Chapter: Surface Chemistry

JEE Main 2018 · 15 April · Evening Shift · Online · Chemistry · Surface Chemistry

If x gram of gas is adsorbed by m gram of adsorbent at pressure P...

x

gram of gas is adsorbed by

m

gram of adsorbent at pressure

P

the plot of

\log \frac{x}{\mathrm{~m}}

versus

\log \mathrm{P}

is linear. The slope of the plot is: (

\mathrm{m}

and

\mathrm{k}

are constants and

n>1

)

Options

A $\log \mathrm{k}$
B $\frac{1}{n}$
C $2 \mathrm{k}$
D $\mathrm{n}$

Correct answer

B. $\frac{1}{n}$

Step-by-step solution

According to Freundlich adsorption isotherm.

\begin{aligned} \frac{\mathrm{x}}{\mathrm{m}}=\mathrm{kP}^{\frac{1}{\mathrm{n}}}\\ &\log _{10} \frac{\mathrm{x}}{\mathrm{m}}=\frac{1}{\mathrm{n}} \log _{10} \mathrm{P}+\log _{10} \mathrm{k} \end{aligned}

This is the equation of straight line of type

y=m x+c

Hence slope is

1 / \mathrm{n}(\mathrm{m})

and intercept is

\log _{\mathrm{e}} \mathrm{k}

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