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JEE Main 20253 AprilEvening Shift

Exam: JEE Main
Year: 2025
Date: 3 April
Shift: Evening Shift
Subject: Mathematics
Chapter: Application of Derivatives

JEE Main 2025 · 3 April · Evening Shift · Mathematics · Application of Derivatives

Let f: R arrow R be a function defined by f(x)=\|x+2|-2| x\| . If m...

Let

\mathrm{f}: \mathrm{R} \rightarrow \mathrm{R}

be a function defined by

f(x)=\|x+2|-2| x\|

. If

m

is the number of points of local minima and

n

is the number of points of local maxima of

f

, then

m+n

is $Let f: R arrow R be a function defined by f(x)=\|x+2|-2| x\| . If m is the number of points of local minima and n is$

Options

A $5$
B $3$
C $2$
D $4$

Correct answer

B. $3$

Step-by-step solution

f(x)=\|x+2|-2| x\|

Critical points,

0,-2,2,-\frac{2}{3}

$Let f: R arrow R be a function defined by f(x)=\|x+2|-2| x\| . If m is the number of points of local minima and n is$
No. of maxima

=1

No. of minima

=2

option (2)

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