JEE Main202116 Mar 2021Evening ShiftMathematicsApplication of DerivativesActual
Let f be a real valued function, defined on R - - 1 , 1 and given by f x = 3 log e x - 1 x + 1 - 2 x - 1 . Then in which of the following intervals, function f x is increasing?
Options
- A- ∞ , - 1 ∪ 1 2 , ∞ - 1
- B- ∞ , ∞ - - 1 , 1
- C- 1 , 1 2
- D- ∞ , 1 2 - - 1
Correct answer
A. - ∞ , - 1 ∪ 1 2 , ∞ - 1
Step-by-step solution
f x = 3 log e x - 1 - 3 log e x + 1 - 2 x - 1 f ' x = 3 x - 1 - 3 x + 1 + 2 x - 1 2 f ' x = 4 2 x - 1 x - 1 2 x + 1 f ' x ≥ 0 ⇒    x ∈ - ∞ , - 1 ∪ 1 2 , 1 ∪ 1 , ∞ or - ∞ , - 1 ∪ 1 2 , ∞ - 1