Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202624 January 2026Evening ShiftMathematicsArea Under CurvesActual

Let f( ) denote the area of the region in the first quadrant bounded by x=0, x=1, y²=x and y=| x-5|-|1- x|+ x² . Then (f(0)+f(1)) is equal to

Options

  1. A12
  2. B14
  3. C7
  4. D9

Correct answer

C. 7

Step-by-step solution

For = 0 : curve is y = 5 - 1 = 4 (horizontal line), area = ₀^1 (4 - x ) dx = 4 - 2 3 = 10 3 For = 1 and 0 x 1 : |x-5| = 5-x , |1-x| = 1-x , so y = 4 + x^2 Area = ₀^1 (4 + x^2 - x ) dx = 4 + 1 3 - 2 3 = 11 3 f(0) + f(1) = 10 3 + 11 3 = 7

Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Passage: Consider the curve C₁ given by y = e^ -x for x [0, 10 ] , and the curve C₂ given by y = e^ -x ( x + x) for x [0, 10 ] . Let n be the total number of points of intersection 2026Passage: Consider the ellipses given by x^2 + 4y^2 = 1 and 4x^2 + y^2 = 1 . Question: If is the area of the common region that lies inside both the given ellipses, then the value o 2026The area of the region (x, y) : x^2 - 8x y -x is : 2026The area of the region (x, y) : 0 y 6 - x, y^2 4x - 3, x 0 is: 2026The area of the region R = (x, y): xy 27, 1 y x^2 is equal to: 2026The area of the region bounded by the curves x+3y^2=0 and x+4y^2=1 is equal to: 2026The area of the region (x, y): y - |x|, y |x x|, y 0 is: 2026If the area of the region bounded by 16x^2 - 9y^2 = 144 and 8x - 3y = 24 is A, then 3(A + 6 _e(3)) is equal to _______. 2026 Full Area Under Curves list All JEE Main PYQs