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JEE Main202522 Jan 2025Evening ShiftMathematicsArea Under CurvesActual

The area of the region enclosed by the curves y=x^2-4 x+4 and y^2=16-8 x is :

Options

  1. A8 3
  2. B4 3
  3. C8
  4. D5

Correct answer

A. 8 3

Step-by-step solution

aligned Area & = ₀^2 ( 16-8 x - (x^2-4 x+4 ) ) d x & .= -(16-8 x)^ 3 / 2 12 - x^3 3 +2 x^2+4 x ]₀^2 & = 8 3 aligned

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