Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202226 Jun 2022Morning ShiftMathematicsArea Under CurvesActual

The area bounded by the curve y = x 2 - 9 and the line y = 3 is

Options

  1. A8 6 - 16 12 - 72
  2. B8 6 + 8 12 - 72
  3. C16 6 + 16 12 - 72
  4. D16 6 - 16 12 - 64

Correct answer

C. 16 6 + 16 12 - 72

Step-by-step solution

We first find the points of intersection of the curves y = x 2 - 9 and y = 3 which gives, x 2 - 9 = 3 ⇒ x 2 - 9 = ± 3 ⇒ x 2 = 12 (or) x 2 = 6 ⇒ x = ± 12 (or) x = ± 6 The graphs of the two curves are shown in figure We have to find the area of the shaded region. Required area = 2 A 1 + 2 A 2 ( ∵ The areas A 1 & A 2 are symmetrical about y - axis ) where A 1 = ∫ 0 6 9 - x 2 − 3 d x A 1 = ∫ 0 6 6 - x 2 d x = 6 x - x 3 3 0 6 = 6 6 - 6 6 3 = 12 6 3 = 4 6 A 2 = &#8

Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Passage: Consider the curve C₁ given by y = e^ -x for x [0, 10 ] , and the curve C₂ given by y = e^ -x ( x + x) for x [0, 10 ] . Let n be the total number of points of intersection 2026Passage: Consider the ellipses given by x^2 + 4y^2 = 1 and 4x^2 + y^2 = 1 . Question: If is the area of the common region that lies inside both the given ellipses, then the value o 2026The area of the region (x, y) : x^2 - 8x y -x is : 2026The area of the region (x, y) : 0 y 6 - x, y^2 4x - 3, x 0 is: 2026The area of the region R = (x, y): xy 27, 1 y x^2 is equal to: 2026The area of the region bounded by the curves x+3y^2=0 and x+4y^2=1 is equal to: 2026The area of the region (x, y): y - |x|, y |x x|, y 0 is: 2026If the area of the region bounded by 16x^2 - 9y^2 = 144 and 8x - 3y = 24 is A, then 3(A + 6 _e(3)) is equal to _______. 2026 Full Area Under Curves list All JEE Main PYQs