Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main20202 Sep 2020Morning ShiftMathematicsArea Under CurvesActual

Area (in sq. units) of the region outside x 2 + y 3 = 1 and inside the ellipse x 2 4 + y 2 9 = 1 is

Options

  1. A6 π − 2
  2. B3 π - 2
  3. C3 4 - π
  4. D6 4 − π

Correct answer

A. 6 π − 2

Step-by-step solution

Area of ellipse = π a b = 6 π Area enclosed by | x | 2 + | y | 3 = 1 is = 4 × 1 2 2 3 = 12 So, required area = 6 π - 12 sq. units

Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Passage: Consider the curve C₁ given by y = e^ -x for x [0, 10 ] , and the curve C₂ given by y = e^ -x ( x + x) for x [0, 10 ] . Let n be the total number of points of intersection 2026Passage: Consider the ellipses given by x^2 + 4y^2 = 1 and 4x^2 + y^2 = 1 . Question: If is the area of the common region that lies inside both the given ellipses, then the value o 2026The area of the region (x, y) : x^2 - 8x y -x is : 2026The area of the region (x, y) : 0 y 6 - x, y^2 4x - 3, x 0 is: 2026The area of the region R = (x, y): xy 27, 1 y x^2 is equal to: 2026The area of the region bounded by the curves x+3y^2=0 and x+4y^2=1 is equal to: 2026The area of the region (x, y): y - |x|, y |x x|, y 0 is: 2026If the area of the region bounded by 16x^2 - 9y^2 = 144 and 8x - 3y = 24 is A, then 3(A + 6 _e(3)) is equal to _______. 2026 Full Area Under Curves list All JEE Main PYQs