Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main201912 Apr 2019Morning ShiftMathematicsArea Under CurvesActual

If the area (in sq. units) of the region x , y : y 2 ≤ 4 x , x + y ≤ 1 , x ≥ 0 , y ≥ 0 is a 2 + b , then a - b is equal to

Options

  1. A6
  2. B10 3
  3. C- 2 3
  4. D8 3

Correct answer

A. 6

Step-by-step solution

The given equations are, y 2 = 4 x   &   x + y = 1 ⇒ y 2 = 4 1 - y ⇒ y 2 + 4 y - 4 = 0   ⇒ y = 2 2 - 2 ∴ Required Area = ∫ 0 2 2 - 2 1 - y - y 2 4 d x = y - y 2 2 - y 3 12 0 2 2 - 2 = 2 2 - 2 - 2 2 - 2 2 2 - 2 2 - 2 3 12 - 0 = 2 2 - 2 1 - 2 - 1 - 2 - 1 2 3 = - 10 3 + 8 2 3 ⇒ - 10 3 + 8 2 3 = a 2 + b   ⇒ a = 8 3 ,   b = - 10 3 ∴   a - b = 8 3 + 10 3 = 6

Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Passage: Consider the curve C₁ given by y = e^ -x for x [0, 10 ] , and the curve C₂ given by y = e^ -x ( x + x) for x [0, 10 ] . Let n be the total number of points of intersection 2026Passage: Consider the ellipses given by x^2 + 4y^2 = 1 and 4x^2 + y^2 = 1 . Question: If is the area of the common region that lies inside both the given ellipses, then the value o 2026The area of the region (x, y) : x^2 - 8x y -x is : 2026The area of the region (x, y) : 0 y 6 - x, y^2 4x - 3, x 0 is: 2026The area of the region R = (x, y): xy 27, 1 y x^2 is equal to: 2026The area of the region bounded by the curves x+3y^2=0 and x+4y^2=1 is equal to: 2026The area of the region (x, y): y - |x|, y |x x|, y 0 is: 2026If the area of the region bounded by 16x^2 - 9y^2 = 144 and 8x - 3y = 24 is A, then 3(A + 6 _e(3)) is equal to _______. 2026 Full Area Under Curves list All JEE Main PYQs