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JEE Main 202430 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
30 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Binomial Theorem

JEE Main 2024 · 30 January · Morning Shift · Mathematics · Binomial Theorem

Number of integral terms in the expansion of \ 7 ^ ((1)/(2)) + 11 ^...

Number of integral terms in the expansion of {\left\{{7}^{\left(\dfrac{1}{2}\right)} + {11}^{\left(\dfrac{1}{6}\right)}\right\}}^{824} is equal to ______.

Correct answer

0

Step-by-step solution

We know that,

General term in expansion of ((7)1/2+(11)1/6)824 isgivenby,</p><p>{\left(( 7{)}^{1 / 2} + ( 11{)}^{1 / 6}\right)}^{824} is given by,</p><p>{t}_{r + 1} = Cr 824 \cdot 7\dfrac{824 - r}{2} \cdot 11\dfrac{r}{6}</p><p>Forintegralterm,</p><p>For integral term,rmustbemultipleofmust be multiple of6andshouldbelessthanand should be less than824</p><p>So,theserieswillbe</p><p>So, the series will ber = 0, 6, 12, . . . . . 822</p><p>Now,findingnumberoftermsweget,</p><p></p><p>Now, finding number of terms we get,</p><p>822 = 0 + \left(n - 1\right)6</p><p></p><p>⇒ 137 = \left(n - 1\right)</p><p></p><p>⇒ n = 138</p><p>Hence,totalintegraltermswillbe</p><p>Hence, total integral terms will be138

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