JEE Main202311 Apr 2023Evening ShiftMathematicsBinomial TheoremActual
If the 1011 th term from the end in the binomial expansion of 4 x 5 - 5 2 x 2022 is 1024 times 1011 th term from the beginning, then 32 x is equal to
Options
- A15
- B10
- C12
- D8
Correct answer
B. 10
Step-by-step solution
Given, The 1011 th term from the end in the binomial expansion of 4 x 5 - 5 2 x 2022 is 1024 times 1011 th term from the beginning, So, according to question we have, T 1013 T 1011 = 1024 ⇒ C 1012 2022 4 x 5 1010 · - 5 2 x 1012 C 1010 2022 4 x 5 1012 - 5 2 x 1010 = 1024 ⇒ - 5 2 x 2 4 x 5 2 = 1024 ⇒ 5 4 2 6 x 4 = 2 10 ⇒ 5 x 4 = 2 16 ⇒ x = 5 16 ⇒ 32 x = 10 Note this question was bonus in Jee Main 2023 April session as answer key was not matching, so we have modified the questi