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JEE Main 202311 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
11 April
Shift
Evening Shift
Subject
Mathematics
Chapter
Binomial Theorem

JEE Main 2023 · 11 April · Evening Shift · Mathematics · Binomial Theorem

If the 1011 ^ th term from the end in the binomial expansion of...

If the 1011th{1011}^{th} term from the end in the binomial expansion of (4x5−52x)2022is{\left(\dfrac{4x}{5} - \dfrac{5}{2x}\right)}^{2022} is1024timestimes{1011}^{th}termfromthebeginning,thenterm from the beginning, then32\left|x\right| is equal to

Options

  1. A1515

  2. B1010
  3. C1212
  4. D88

Correct answer

B. 1010

Step-by-step solution

Given,

The 1011th{1011}^{th} term from the end in the binomial expansion of (4x5−52x)2022is{\left(\dfrac{4x}{5} - \dfrac{5}{2x}\right)}^{2022} is1024timestimes{1011}^{th}termfromthebeginning,</p><p>So,accordingtoquestionwehave,term from the beginning,</p><p>So, according to question we have,\dfrac{{T}_{1013}}{{T}_{1011}} = 1024<br/><br />⇒ \dfrac{C1012 2022 {\left(\dfrac{4x}{5}\right)}^{1010} \cdot {\left(\dfrac{- 5}{2x}\right)}^{1012}}{C1010 2022 {\left(\dfrac{4x}{5}\right)}^{1012}{\left(\dfrac{- 5}{2x}\right)}^{1010}} = 1024</p><p></p><p>⇒ \dfrac{{\left(\dfrac{- 5}{2x}\right)}^{2}}{{\left(\dfrac{4x}{5}\right)}^{2}} = 1024</p><p></p><p>⇒ \dfrac{{5}^{4}}{{2}^{6}{x}^{4}} = {2}^{10}</p><p></p><p>⇒ {\left(\dfrac{5}{x}\right)}^{4} = {2}^{16}</p><p></p><p>⇒ \left|x\right| = \dfrac{5}{16}</p><p></p><p>⇒ 32\left|x\right| = 10$

Note this question was bonus in Jee Main 2023 April session as answer key was not matching, so we have modified the question.

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