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JEE Main 202324 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
24 January
Shift
Evening Shift
Subject
Mathematics
Chapter
Binomial Theorem

JEE Main 2023 · 24 January · Evening Shift · Mathematics · Binomial Theorem

If (C1 30) ^ 2 + 2 (C2 30) ^ 2 + 3 (C3 30) ^ 2 . . . . . . . . . ....

If (C130)2+2(C230)2+3(C330)2..........30(C3030)2=α60!(30!)2{\left(C1 30\right)}^{2} + 2{\left(C2 30\right)}^{2} + 3{\left(C3 30\right)}^{2} . . . . . . . . . . 30{\left(C30 30\right)}^{2} = \dfrac{\alpha60 !}{{\left(30 !\right)}^{2}}, then α\alpha is equal to

Options

  1. A3030
  2. B6060
  3. C1515
  4. D1010

Correct answer

C. 1515

Step-by-step solution

Let,

S=0(C130)2+1(C130)2+2(C230)2+3(C330)2..........30(C3030)2S = 0{\left(C1 30\right)}^{2} + 1{\left(C1 30\right)}^{2} + 2{\left(C2 30\right)}^{2} + 3{\left(C3 30\right)}^{2} . . . . . . . . . . 30{\left(C30 30\right)}^{2}

Now rewriting the above expression we get,

S=30(C3030)2+29(C2930)2+28(C2830)2+27(C2730)2..........+0(C030)2S = 30{\left(C30 30\right)}^{2} + 29{\left(C29 30\right)}^{2} + 28{\left(C28 30\right)}^{2} + 27{\left(C27 30\right)}^{2} . . . . . . . . . . + 0{\left(C0 30\right)}^{2}

Now adding both the equation we get,

2S=30[(C130)2+(C130)2+(C230)2+(C330)2..........(C3030)2]2S = 30\left[{\left(C1 30\right)}^{2} + {\left(C1 30\right)}^{2} + {\left(C2 30\right)}^{2} + {\left(C3 30\right)}^{2} . . . . . . . . . . {\left(C30 30\right)}^{2}\right]

⇒S=15[C302×30]⇒ S = 15\left[C30 2 \times 30\right]

⇒S=15[C3060]=15×60!(30!)2⇒ S = 15\left[C30 60\right] = 15 \times \dfrac{60 !}{{\left(30 !\right)}^{2}}

Now comparing with S=α60!(30!)2S = \dfrac{\alpha60 !}{{\left(30 !\right)}^{2}},

We get α=15\alpha = 15

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