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JEE Main 20198 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
8 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Binomial Theorem

JEE Main 2019 · 8 April · Morning Shift · Mathematics · Binomial Theorem

The sum of the co-efficient of all even degree terms in x in the...

The sum of the co-efficient of all even degree terms in xx in the expansion of (x+x3−1){\left(x + \sqrt{{x}^{3} - 1}\right)}^{6}{+ \left(x - \sqrt{{x}^{3} - 1}\right)}^{6}, \left(x > 1\right) is equal to

Options

  1. A2626
  2. B3232
  3. C2424
  4. D2929

Correct answer

C. 2424

Step-by-step solution

(x+x3−1)6+(x−x3−1)6{\left(x + \sqrt{{x}^{3} - 1}\right)}^{6} + {\left(x - \sqrt{{x}^{3} - 1}\right)}^{6}

=2(6C0x6+6C2x4(x3−1)+6C4x2(x3−1)2+6C6(x3−1)3)= 2\left({}^{6}{C}_{0}{x}^{6}{+}^{6}{C}_{2}{x}^{4}\left({x}^{3} - 1\right){+}^{6}{C}_{4}{x}^{2}{\left({x}^{3} - 1\right)}^{2}{+}^{6}{C}_{6}{\left({x}^{3} - 1\right)}^{3}\right)

=2(6C0x6+6C2(x7−x4)+6C4x2(x6−2x3+1)+6C6(x9−3x6+3x3−1))= 2\left({}^{6}{C}_{0}{x}^{6}{+}^{6}{C}_{2}\left({x}^{7} - {x}^{4}\right){+}^{6}{C}_{4}{x}^{2}\left({x}^{6} - 2{x}^{3} + 1\right){+}^{6}{C}_{6}\left({x}^{9} - 3{x}^{6} + 3{x}^{3} - 1\right)\right)

∴∴ Sum of the coefficient of even power of xx

=2(6C0−6C2+6C4+6C4−3−6C6)= 2\left(6{C}_{0}{-}^{6}{C}_{2}{+}^{6}{C}_{4}{+}^{6}{C}_{4} - 3{-}^{6}{C}_{6}\right)

=2(1−15+15+15−3−1)=24= 2\left(1 - 15 + 15 + 15 - 3 - 1\right) = 24

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