JEE Main202624 January 2026Morning ShiftMathematicsCircleActual
Let S = z C : | z-6 i z-2 i |=1 . and . | z-8+2 i z+2 i |= 3 5 . Then _ z ~s |z|² is equal to
Options
- A385
- B398
- C413
- D423
Correct answer
A. 385
Step-by-step solution
Solving | z - 6i z - 2i | = 1 y = 4 .....(1) (where z = x + iy ) Now solving | z - 8 + 2i z + 2i | = 3 5 x^2 + y^2 - 25x + 4y + 104 = 0 .....(2) Solving (1) & (2) z = 17 + 4i & 8 + 4i |z|^2 = (17)^2 + (4)^2 + (8)^2 + (4)^2 = 385