Equation of the tangent to the circle, at the point 1 , - 1 , whose center, is the point of intersection of the straight lines x - y = 1 and 2 x + y = 3 is:

Step-by-step solution

Point of intersection of lines x - y = 1 and 2 x + y = 3 O is 4 3 , 1 3 Slope of O P = 1 3 + 1 4 3 - 1 = 4 3 1 3 = 4 Slope of tangent = - 1 4 ⇒ Equation of tangent : y + 1 =   - 1 4 x - 1 ⇒ 4 y + 4 = - x + 1 ⇒ x + 4 y + 3 = 0