JEE Main2004MathematicsCircleActual
If a circle passes through the point (a, b) and cuts the circle x^2+y^2=4 orthogonally, then the locus of its centre is
Options
- A2 a x+2 b y+ (a^2+b^2+4 )=0
- B2 a x+2 b y- (a^2+b^2+4 )=0
- C2 a x-2 b y+ (a^2+b^2+4 )=0
- D2 a x-2 b y- (a^2+b^2+4 )=0
Correct answer
B. 2 a x+2 b y- (a^2+b^2+4 )=0
Step-by-step solution
Let the circle be x^2+y^2+2 g x+2 f y+c=0 c=4 and it passes through (a, b) a ^2+ b ^2+2 ga +2 fb +4=0 Hence locus of the centre is 2 a x+2 b y- (a^2+b^2+4 )=0