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If the lines 2 x+3 y+1=0 and 3 x-y-4=0 lie along diameters of a circle of circumference 10 , then the equation of the circle is

Options

  1. Ax^2+y^2-2 x+2 y-23=0
  2. Bx^2+y^2-2 x-2 y-23=0
  3. Cx^2+y^2+2 x+2 y-23=0
  4. Dx^2+y^2+2 x-2 y-23=0

Correct answer

A. x^2+y^2-2 x+2 y-23=0

Step-by-step solution

Intersection of given lines is the centre of the circle i.e. (1,-1) Circumference =10 radius r=5 equation of circle is x^2+y^2-2 x+2 y-23=0

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