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JEE Main2004MathematicsCircleActual

The intercept on the line y=x by the circle x^2+y^2-2 x=0 is A B . Equation of the circle on AB as a diameter is

Options

  1. Ax^2+y^2-x-y=0
  2. Bx^2+y^2-x+y=0
  3. Cx ^2+ y ^2+ x + y =0
  4. Dx^2+y^2+x-y=0

Correct answer

A. x^2+y^2-x-y=0

Step-by-step solution

Points of intersection of line y=x with x^2+y^2-2 x=0 are (0,0) and (1,1) hence equation of circle having end points of diameter (0,0) and (1,1) is x^2+y^2-x-y=0

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