JEE Main2003MathematicsCircleActual
The lines 2 x -3 y =5 and 3 x -4 y =7 are diameters of a circle having area as 154 sq. units. Then the equation of the circle is
Options
- Ax^2+y^2-2 x+2 y=62
- Bx^2+y^2+2 x-2 y=62
- Cx^2+y^2+2 x-2 y=47
- Dx^2+y^2-2 x+2 y=47
Correct answer
D. x^2+y^2-2 x+2 y=47
Step-by-step solution
r ^2=154 r =7 For centre on solving equation 2 x-3 y=5 & 3 x-4 y=7 or x=1, y=1 centre =(1,-1) Equation of circle, ( x -1)^2+( y +1)^2=7^2x^2+y^2-2 x+2 y=47