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JEE Main 20257 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Continuity and Differentiability

JEE Main 2025 · 7 April · Morning Shift · Mathematics · Continuity and Differentiability

The number of points of discontinuity of the function f(x)=[ x^2 2...

The number of points of discontinuity of the function f(x)=[x22]−[x],x∈[0,4]f(\mathrm{x})=\left[\frac{\mathrm{x}^2}{2}\right]-[\sqrt{\mathrm{x}}], \mathrm{x} \in[0,4], where [⋅][\cdot] denotes the greatest integer function is ________

Correct answer

0

Step-by-step solution

Check for [x22]\left[\frac{x^2}{2}\right] and [x][\sqrt{x}] becomes integers.
{0,1,2,2,6,8,10,12,14,4}\{0,1, \sqrt{2}, 2, \sqrt{6}, \sqrt{8}, \sqrt{10}, \sqrt{12}, \sqrt{14}, 4\}
Continuous at 0+0^{+}, continuous at 4−[x22]=[x]4^{-} \left[\frac{x^2}{2}\right]=[\sqrt{x}], occurs at x=2x=\sqrt{2}
⇒\Rightarrow Not continuous
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