JEE Main 202528 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2025
- Date
- 28 January
- Shift
- Morning Shift
- Subject
- Mathematics
- Chapter
- Continuity and Differentiability
JEE Main 2025 · 28 January · Morning Shift · Mathematics · Continuity and Differentiability
Let f(x)=\ array lc 3 x, & x 0 \ 1+x+[x], x+2[x]\ , & 0 ≤ x ≤ 2 5,...
Let \mathrm{f}(x)=\left\{\right.
where [.] denotes greatest integer function. If and are the number of points, where f is not continuous and is not differentiable, respectively, then equals __________![Let f(x)=\ array lc 3 x, & x 0 \ 1+x+[x], x+2[x]\ , & 0 ≤ x ≤ 2 5, & x 2, array . where [.] denotes greatest integer](/api/proxy-image?clean=1&b=aHR0cHM6Ly9jZG4tcXVlc3Rpb24tcG9vbC5nZXRtYXJrcy5hcHAvcHlxL2plZV9tYWluL3lGaGtsMGNHaUQ5bnpRRGxmMjkyNGRxcElYYlREVzhvMnA5VDFIY21WM1Uub3JpZ2luYWwuZnVsbHNpemUucG5n)
Correct answer
0
Step-by-step solution
f(x)=\left\{\right.
f(x)=\left\{\right.![Let f(x)=\ array lc 3 x, & x 0 \ 1+x+[x], x+2[x]\ , & 0 ≤ x ≤ 2 5, & x 2, array . where [.] denotes greatest integer](/api/proxy-image?clean=1&b=aHR0cHM6Ly9jZG4tcXVlc3Rpb24tcG9vbC5nZXRtYXJrcy5hcHAvcHlxL2plZV9tYWluL3lGaGtsMGNHaUQ5bnpRRGxmMjkyNGRxcElYYlREVzhvMnA5VDFIY21WM1Uub3JpZ2luYWwuZnVsbHNpemUucG5n)
Not continuous at Not diff. at
Not continuous at Not diff. at