JEE Main202124 Feb 2021Morning ShiftMathematicsContinuity and DifferentiabilityActual
If f : R → R is a function defined by f x = x - 1 cos 2 x - 1 2 π , where · denotes the greatest integer function, then f is:
Options
- Adiscontinuous only at x = 1
- Bdiscontinuous at all integral values of x except at x = 1
- Ccontinuous only at x = 1
- Dcontinuous for every real x
Correct answer
D. continuous for every real x
Step-by-step solution
Doubtful points are x = n ,   n ∈ I L . H . L   = lim x → n - x - 1 cos 2 x - 1 2 π = n - 2 cos 2 n - 1 2 π = 0 R . H . L   = lim x → n + x - 1 cos 2 x - 1 2 π = n - 1 cos 2 n - 1 2 π = 0 f n = 0 Hence continuous.