JEE Main 20198 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 8 April
- Shift
- Evening Shift
- Subject
- Mathematics
- Chapter
- Continuity and Differentiability
JEE Main 2019 · 8 April · Evening Shift · Mathematics · Continuity and Differentiability
Let f: [- 1,3] → R be defined as f(x) = \ array ll |x| + [x], x +...
Let be defined as
f\left(x\right) = \left\{$\begin{array}{ll}- 1 \le x < 1 \\ 1 \le x < 2 \\ 2 \le x \le 3,\end{array}\right
Where \left[t\right] denotes. Then, is discontinuous at:$
f\left(x\right) = \left\{$\begin{array}{ll}- 1 \le x < 1 \\ 1 \le x < 2 \\ 2 \le x \le 3,\end{array}\right
Where \left[t\right] denotes. Then, is discontinuous at:$
Options
- AOnly one point
- BOnly two points
- CFour or more points
- DOnly three points
Correct answer
D. Only three points
Step-by-step solution
f\left(x\right) = \left\{\right)</p><p>= \left\{\right)
At changes its definition.
At is discontinuous at
is discontinuous at
is continuous at
is discontinuous at
Points of discontinuity are