JEE Main201911 Jan 2019Evening ShiftMathematicsContinuity and DifferentiabilityActual
Let K be the set of all real values of x where the function f(x)= |x|-|x|+2(x- ) |x| is not differentiable. Then the set K is equal to :
Options
- A(an empty set)
- B(
- C0
- D0,
Correct answer
A. (an empty set)
Step-by-step solution
f(x)= |x|-|x|+2(x- ) |x| There are two cases, Case (1), x>0f(x)= x-x+2(x- ) xf^ (x)= x-1+2(1-0) x-2 (x- )f^ (x)=3 x-2(x- ) x-1 Then, function f(x) is differentiable for all x>0 Case (2) x < 0f(x)=- x+x+2(x- ) xf^ (x)=- x+1-2(x- ) x+2 xf^ (x)= x+1-2(x- ) x Then, function f(x) is differentiable for all x < 0 Now check for x=0f^ (0^ * ) R HD =3-1=2f^ (0) L . H.D. =1+1=2 L . HD = R . H.D Then, function f(x) is differentiable for x=0 . So it is differentiable everywhere Hence, k=