JEE Main 201910 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 10 January
- Shift
- Morning Shift
- Subject
- Mathematics
- Chapter
- Continuity and Differentiability
JEE Main 2019 · 10 January · Morning Shift · Mathematics · Continuity and Differentiability
Let f(x) = \ cases max(|x|, x ^ 2 ), & |x| ≤ 2 8 - 2|x|, & 2 < |x|...
Let f\left(x\right) = \left\{\begin{cases}max\left(\left|x\right|, {x}^{2}\right), & \left|x\right| \le 2 \\ 8 - 2\left|x\right|, & 2 < \left|x\right| \le 4\end{cases}.\right) LetS at which is not differentiable. Then $S
Options
- Aequals
- Bequals
- Cis an empty set
- Dequal
Correct answer
A. equals
Step-by-step solution
Given function is f\left(x\right) = \left\{\begin{cases}max\left(\left|x\right|, {x}^{2}\right), & \left|x\right| \le 2 \\ 8 - 2\left|x\right|, & 2 < \left|x\right| \le 4\end{cases}\right)</p><p>The graph of the function, is</p><p><img alt="" src="https://cdn-question-pool.Quantrex.app/pyq/jee_main/0586fe52-962a-400c-b729-b64749754feb-139.png" style="width: 350px; height: 210px;" /></p><p>We know that, a function is not differentiable at a point where its graph has a sharp corner.</p><p>And, from the graph we can easily conclude thatf is non-derivable at
Hence, the set