JEE Main2015MathematicsContinuity and DifferentiabilityActual
If the function g x = k x + 1 , 0 ≤ x ≤ 3 m x + 2 , 3 < x ≤ 5 is differentiable, then the value of k + m is
Options
- A4
- B2
- C16 5
- D10 3
Correct answer
B. 2
Step-by-step solution
LHD at x = 3 lim x ⟶ 3 - ⁡ k x + 1 - 2 k x - 3 =   lim x → 3 - ⁡k x - 3 x - 3 . 1 x + 1 + 2 = k 4 RHD at x = 3 lim x → 3 + ⁡ m x + 2 - 2 k x - 3 Since this limit exists if 3 m + 2 - 2 k = 0   . . . i ( 0 0 form) So, lim x → 3 + ⁡ m x + 2 - 3 m + 2 x - 3 = m Hence m = k 4   … ii From i   &   ii m = 2 5   &   k = 8 5     ⇒ k + m = 2