JEE Main 2022 · 26 July · Evening Shift · Mathematics · Differentiation
D. 444
For loge2ddx(logcosxcosecx)\log_{e}2\dfrac{d}{dx}\left(\log_{\cos x} cosec x\right)loge2dxd(logcosxcosecx)let, y=logcosxcosecxy = \log_{\cos x} cosec xy=logcosxcosecxi.e. y=−ln(sinx)ln(cosx)y = - \dfrac{\ln \left(\sin x\right)}{\ln \left(\cos x\right)}y=−ln(cosx)ln(sinx)⇒dydx=−[cotx⋅ln(cosx)+tanx⋅ln(sinx)](ln(cosx))2⇒ \dfrac{dy}{dx} = - \dfrac{\left[\cot x \cdot \ln \left(\cos x\right) + \tan x \cdot \ln \left(\sin x\right)\right]}{{\left(\ln \left(\cos x\right)\right)}^{2}}⇒dxdy=−(ln(cosx))2[cotx⋅ln(cosx)+tanx⋅ln(sinx)]Now (dydx)x=π4=−[cotπ4⋅ln(cosπ4)+tanπ4⋅ln(sinπ4)](ln(cosπ4))2{\left(\dfrac{dy}{dx}\right)}_{x = \dfrac{\pi}{4}} = - \dfrac{\left[cot\dfrac{\pi}{4} \cdot \ln \left(cos\dfrac{\pi}{4}\right) + tan\dfrac{\pi}{4} \cdot \ln \left(sin\dfrac{\pi}{4}\right)\right]}{{\left(\ln \left(cos\dfrac{\pi}{4}\right)\right)}^{2}}(dxdy)x=4π=−(ln(cos4π))2[cot4π⋅ln(cos4π)+tan4π⋅ln(sin4π)]=4ln2= \dfrac{4}{\ln 2}=ln24⇒loge2⋅4ln2=4⇒ \log_{e}2 \cdot \dfrac{4}{\ln 2} = 4⇒loge2⋅ln24=4
For loge2ddx(logcosxcosecx)\log_{e}2\dfrac{d}{dx}\left(\log_{\cos x} cosec x\right)loge2dxd(logcosxcosecx)
let, y=logcosxcosecxy = \log_{\cos x} cosec xy=logcosxcosecx
i.e. y=−ln(sinx)ln(cosx)y = - \dfrac{\ln \left(\sin x\right)}{\ln \left(\cos x\right)}y=−ln(cosx)ln(sinx)
⇒dydx=−[cotx⋅ln(cosx)+tanx⋅ln(sinx)](ln(cosx))2⇒ \dfrac{dy}{dx} = - \dfrac{\left[\cot x \cdot \ln \left(\cos x\right) + \tan x \cdot \ln \left(\sin x\right)\right]}{{\left(\ln \left(\cos x\right)\right)}^{2}}⇒dxdy=−(ln(cosx))2[cotx⋅ln(cosx)+tanx⋅ln(sinx)]
Now (dydx)x=π4=−[cotπ4⋅ln(cosπ4)+tanπ4⋅ln(sinπ4)](ln(cosπ4))2{\left(\dfrac{dy}{dx}\right)}_{x = \dfrac{\pi}{4}} = - \dfrac{\left[cot\dfrac{\pi}{4} \cdot \ln \left(cos\dfrac{\pi}{4}\right) + tan\dfrac{\pi}{4} \cdot \ln \left(sin\dfrac{\pi}{4}\right)\right]}{{\left(\ln \left(cos\dfrac{\pi}{4}\right)\right)}^{2}}(dxdy)x=4π=−(ln(cos4π))2[cot4π⋅ln(cos4π)+tan4π⋅ln(sin4π)]
=4ln2= \dfrac{4}{\ln 2}=ln24
⇒loge2⋅4ln2=4⇒ \log_{e}2 \cdot \dfrac{4}{\ln 2} = 4⇒loge2⋅ln24=4