JEE Main 202125 JulyMorning Shift
- Exam
- JEE Main
- Year
- 2021
- Date
- 25 July
- Shift
- Morning Shift
- Subject
- Mathematics
- Chapter
- Functions
JEE Main 2021 · 25 July · Morning Shift · Mathematics · Functions
Let g: N → N be defined as g ( 3n + 1 ) = 3n + 2 g ( 3n + 2 ) = 3n...
Let be defined as
, for all
Then which of the following statements is true ?
Options
- AThere exists an onto function such that
- BThere exists a one-one function such
that - C
- DThere exists a function such that
Correct answer
A. There exists an onto function such that
Step-by-step solution
g: N \to Ng ( 3n + 1 ) = 3n + 2g ( 3n + 2 ) = 3n + 3g ( 3n + 3 ) = 3n + 1g\left(x\right) = \left\{\right)
g\left(g\left(x\right)\right) = \left\{\right)</p><p>g\left(g\left(g\left(x\right)\right)\right) = \left\{\right)
If is a one-one function such that , which is not the case
If is an onto function such that one possibility is
f\left(x\right) = \left\{\begin{cases}n; & x = 3n + 1 \\ n; & x = 3n + 2 \\ n; & x = 3n + 3\end{cases}\right; n \in N
Here is onto, also