JEE Main 20199 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2019
- Date
- 9 April
- Shift
- Evening Shift
- Subject
- Mathematics
- Chapter
- Functions
JEE Main 2019 · 9 April · Evening Shift · Mathematics · Functions
The domain of the definition of the function f (x) = 1 4 - x ^ 2 +...
The domain of the definition of the function \left(x\right) = \dfrac{1}{4 - {x}^{2}} + \log_{10} is:
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
We know that is defined when and for a fraction to be defined its denominator must be non-zero.
Thus, the given function is defined only when
and
and
The wavy curve for the inequality is
and
Hence, domain is \left(- 1, 0\right) \cup \left(1, 2\right) \cup \left(2, \infty\right) .