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JEE Main2003MathematicsFunctionsActual

The function f(x)= (x+ x^2+1 ) , is

Options

  1. Aneither an even nor an odd function
  2. Ban even function
  3. Can odd function
  4. Da periodic function

Correct answer

C. an odd function

Step-by-step solution

f(x)= (x+ x^2+1 )f(-x)=- (x+ x^2+1 )f(-x)=-f(x) , i.e., f(x) is an odd function.

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