JEE Main20254 Apr 2025Morning ShiftMathematicsInverse Trigonometric FunctionsActual
Considering the principal values of the inverse trigonometric functions, ⁻¹ ( 3 2 x+ 1 2 1-x^2 ),- 1 2 x 1 2 , is equal to
Options
- A4 + ⁻¹ x
- B6 + ⁻¹ x
- C-5 6 - ⁻¹ x
- D5 6 - ⁻¹ x
Correct answer
B. 6 + ⁻¹ x
Step-by-step solution
aligned & ⁻¹ ( 3 2 x+ 1 2 1-x^2 ), -1 2 x 1 2 & Let ⁻¹(x)= - 6 4 & x= , then & ⁻¹ ( 3 2 + 1 2 ) & ⁻¹ ( ( + 6 ) )= + 6 & ⁻¹(x)+ 6 aligned