JEE Main202227 Jun 2022Morning ShiftMathematicsInverse Trigonometric FunctionsActual
sin - 1 sin 2 π 3 + cos - 1 cos 7 π 6 + tan - 1 tan 3 π 4 is equal to
Options
- A11 π 12
- B17 π 12
- C31 π 12
- D- 3 π 4
Correct answer
A. 11 π 12
Step-by-step solution
Given, sin - 1 sin 2 π 3 + cos - 1 cos 7 π 6 + tan - 1 tan 3 π 4 Now simplifying each term we get, sin - 1 sin 2 π 3 = π - 2 π 3 = π 3 cos - 1 cos 7 π 6 = 2 π - 7 π 6 = 5 π 6 tan - 1 tan 3 π 4 = 3 π 4 - π = - π 4 sin - 1 sin 2 π 3 + cos - 1 cos 7 π 6 + tan - 1 tan 3 π 4 = π 3 + 5 π 6 - π 4 = 11 π 12