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JEE Main20211 Sep 2021Evening ShiftMathematicsInverse Trigonometric FunctionsActual

cos - 1 ( cos ( - 5 ) ) + sin - 1 ( sin ( 6 ) ) - tan - 1 ( tan ( 12 ) ) is equal to : (The inverse trigonometric functions take the principal values)

Options

  1. A3 π + 1
  2. B3 π - 11
  3. C4 π - 11
  4. D4 π - 9

Correct answer

C. 4 π - 11

Step-by-step solution

cos - 1 ( cos ( - 5 ) ) + sin - 1 sin ( 6 ) - tan - 1 ( tan ( 12 ) ) = 2 π - 5 + ( - 2 π + 6 ) - ( 12 - 4 π ) = 4 π - 11

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