JEE Main202117 Mar 2021Morning ShiftMathematicsInverse Trigonometric FunctionsActual
The sum of possible values of x for tan - 1 x + 1 + cot - 1 1 x - 1 = tan - 1 8 31 is:
Options
- A- 32 4
- B- 31 4
- C- 30 4
- D- 33 4
Correct answer
A. - 32 4
Step-by-step solution
Given tan - 1 x + 1 + cot - 1 1 x - 1 = tan - 1 8 31 ⇒ tan - 1 x + 1 + tan - 1 x - 1 = tan - 1 8 31 ,       ∴ tan - 1 x = cot - 1 1 x ,   x > 0 ⇒ tan - 1 x + 1 + x - 1 1 - x + 1 x - 1 = tan - 1 8 31 ⇒ tan - 1 2 x 1 - x + 1 x - 1 = tan - 1 8 31 Taking tangent both the sides we get, ( x + 1 ) + ( x - 1 ) 1 - x 2 - 1 = 8 31 ⇒ 2 x 2 - x 2 = 8 31 ⇒ 4 x 2 + 31 x - 8 = 0 ⇒ x = - 8 , 1 4 But, if x = 1 4 tan - 1 x + 1 ∈ 0 , π 2 and cot - 1 1 x - 1