JEE Main 20202 SeptemberEvening Shift
- Exam
- JEE Main
- Year
- 2020
- Date
- 2 September
- Shift
- Evening Shift
- Subject
- Mathematics
- Chapter
- Inverse Trigonometric Functions
JEE Main 2020 · 2 September · Evening Shift · Mathematics · Inverse Trigonometric Functions
If y = ∑ _ k = 1 ^ 6 k ^ - 1 \ (3)/(5)coskx - (4)/(5)sinkx\ then...
If then at is
Correct answer
91
Step-by-step solution
For, small values near , i.e., \left|x\right| < < . . 1y = \mathop{∑}_{k = 1}^{6}k\cos^{- 1}\left(coskx \cdot cos\alpha - sinkx \cdot sin\alpha\right)
= \mathop{∑}_{k = 1}^{6}k\cos^{- 1}\left(\cos \left(kx + \alpha\right)\right)= \mathop{∑}_{k = 1}^{6}k \left(kx + \alpha\right)= \mathop{∑}_{k = 1}^{6}\left({k}^{2}x + k\alpha\right)
\dfrac{dy}{dx} =\mathop{∑}_{k = 1}^{6}{k}^{2} = \dfrac{6\left(7\right)\left(13\right)}{6} = 91