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JEE Main 2002
Exam
JEE Main
Year
2002
Subject
Mathematics
Chapter
Mathematical Induction

JEE Main 2002 · Mathematics · Mathematical Induction

If a_n= 7+ 7+ 7+ . having n radical signs then by methods of...

If an=7+7+7+….a_n=\sqrt{7+\sqrt{7+\sqrt{7+\ldots .}}} having n\mathrm{n} radical signs then by methods of mathematical induciton which is true

Options

  1. Aan>7∀n≥1a_n>7 \forall n \geq 1
  2. Ban>7∀n≥1\mathrm{a}_{\mathrm{n}}>7 \forall \mathrm{n} \geq 1
  3. Can<4∀n≥1a_n < 4 \forall n \geq 1
  4. Dan<3∀n≥1a_n < 3 \forall \mathrm{n} \geq 1

Correct answer

B. an>7∀n≥1\mathrm{a}_{\mathrm{n}}>7 \forall \mathrm{n} \geq 1

Step-by-step solution

a1=7<7\mathrm{a}_1=\sqrt{7} < 7. Leta m<7_{\mathrm{m}} < 7. Then am+1=7+am⇒am+12=7+am<7+7<14\mathrm{a}_{\mathrm{m}}+1=\sqrt{7+\mathrm{a}_{\mathrm{m}}} \Rightarrow \mathrm{a}_{\mathrm{m}+1}^2=7+\mathrm{a}_{\mathrm{m}} < 7+7 < 14 ⇒am+1<14<7;\Rightarrow \mathrm{a}_{\mathrm{m}+1} < \sqrt{14} < 7 ; So an<7∀n∴an>3\mathrm{a}_{\mathrm{n}} < 7 \forall \mathrm{n} \therefore \mathrm{a}_{\mathrm{n}}>3
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