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JEE Main 20252 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
2 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Probability

JEE Main 2025 · 2 April · Morning Shift · Mathematics · Probability

Three distinct numbers are selected randomly from the set \ 1,2,3,...

Three distinct numbers are selected randomly from the set {1,2,3,……,40}\{1,2,3, \ldots \ldots, 40\}. If the probability, that the selected numbers are in an increasing G.P. is mn\frac{m}{n}, gcd⁡(m,n)=1\operatorname{gcd}(m, n)=1, then m+nm+n is equal to _____.

Correct answer

0

Step-by-step solution

1≤a<ar<ar2≤401 \leq \mathrm{a} \lt \mathrm{ar} \lt \mathrm{ar}^2 \leq 40
(If r∈Nr \in N )
If r=2r=2
1≤a<2a<4a≤401 \leq a \lt 2 a \lt 4 a \leq 40
a∈{1,…….,10}a \in\{1, \ldots \ldots ., 10\} ________ (10 GP)
If r=3r=3
1≤a<3a<9a≤401 \leq a \lt 3 a \lt 9 a \leq 40
a∈{1,2,3,4}\mathrm{a} \in\{1,2,3,4\} ________ ________ (4 GP)
If r=4\mathrm{r}=4
1≤a<4a<16a≤401 \leq a \lt 4 a \lt 16 a \leq 40
a∈{1,2}a \in\{1,2\} ________ ________ (2 GP)
If r=5r=5
1≤a<5a<25a≤401 \leq a \lt 5 a \lt 25 a \leq 40
a∈{1}a \in\{1\} ________ ________ (1 GP)
If r=6r=6
1≤a<6a<36a≤401 \leq a \lt 6 a \lt 36 a \leq 40
a∈{1}\mathrm{a} \in\{1\} ________ ________ (1 GP)
\left(\mathrm{P}=\frac{18}{9880}=\frac{9}{4940}\right)asperNTAforas per NTA for\mathrm{r} \in \mathrm{N}<br/><br/>\mathrm{m}+\mathrm{n}=4949<br/>If<br/>If\underline{r} \notin \mathrm{~N}(alsopossible)<br/>(also possible)<br/>\mathrm{r}=\frac{3}{2}<br/><br/>\operatorname{ar}^2=\frac{9 \mathrm{a}}{4} ; \mathrm{a}=4 \mathrm{k}<br/>\left.(4,6,9)(8,12,18)(12,18,27)(16,24,36)\begin{array}{l}(4,6,9) \\ (8,12,18) \\ (12,18,27) \\ (16,24,36)\end{array}\right\} 4 \mathrm{GP}
r=52ar2=25a4;a=4k(4,10,25)……..(1)GPr=43ar2=16a9→a=9k(9,12,16),(18,24,32)…….(2)GPr=53ar2=25a9;a=9k(9,15,25)……….(1)GPr=54ar2=25a16;a=16k(16,20,25)………..(1)GPr=65ar2=36a25;a=25k(25,30,36)………..(1)GPTotal=18+10=28P=2840C3=289880=72470 m+n=2477\begin{aligned} & \begin{array}{l}\mathrm{r}=\frac{5}{2} \quad \mathrm{ar}^2=\frac{25 \mathrm{a}}{4} ; \mathrm{a}=4 \mathrm{k} \\ \\ \\ (4,10,25) \ldots \ldots . .(1) \mathrm{GP} \\ \mathrm{r}=\frac{4}{3} \quad \mathrm{ar}^2=\frac{16 \mathrm{a}}{9} \rightarrow \mathrm{a}=9 \mathrm{k} \\ \\ \\ (9,12,16),(18,24,32) \ldots \ldots .(2) \mathrm{GP} \\ \mathrm{r}=\frac{5}{3} \quad \mathrm{ar}^2=\frac{25 \mathrm{a}}{9} ; \mathrm{a}=9 \mathrm{k} \\ \\ \quad(9,15,25) \ldots \ldots \ldots .(1) \mathrm{GP} \\ \mathrm{r}=\frac{5}{4} \quad \mathrm{ar}^2=\frac{25 \mathrm{a}}{16} ; \mathrm{a}=16 \mathrm{k}\end{array} \\ & \quad \begin{array}{l}(16,20,25) \ldots \ldots \ldots . .(1) \mathrm{GP} \\ \mathrm{r}=\frac{6}{5} \quad \mathrm{ar}^2=\frac{36 \mathrm{a}}{25} ; \mathrm{a}=25 \mathrm{k}\end{array} \\ & \begin{array}{l}(25,30,36) \ldots \ldots \ldots . .(1) \mathrm{GP} \\ \mathrm{Total}=18+10=28 \\ \mathrm{P}=\frac{28}{40} \mathrm{C}_3=\frac{28}{9880}=\frac{7}{2470} \\ \mathrm{~m}+\mathrm{n}=2477\end{array}\end{aligned}
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