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JEE Main 202524 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
24 January
Shift
Morning Shift
Subject
Mathematics
Chapter
Probability

JEE Main 2025 · 24 January · Morning Shift · Mathematics · Probability

A and B alternately throw a pair of dice. A wins if he throws a sum...

AA and BB alternately throw a pair of dice. AA wins if he throws a sum of 5 before BB throws a sum of 8 , and BB wins if he throws a sum of 8 before AA throws a sum of 5 . The probability, that AA wins if A makes the first throw, is

Options

  1. A817\frac{8}{17}
  2. B919\frac{9}{19}
  3. C917\frac{9}{17}
  4. D819\frac{8}{19}

Correct answer

B. 919\frac{9}{19}

Step-by-step solution

For sum ' 5 ' \rightarrow(1,4),(2,3),(3,2) (4,1) \Rightarrow P(A)=436\frac{4}{36} For sum′8′→(2,6),(3,5),(4,4)Forsum ' 8 ' \rightarrow(2,6),(3,5),(4,4) Forsum ' 5 ' \rightarrow(1,4),(2,3),(3,2) (4,1) \Rightarrow P(A)=436\frac{4}{36} For sum′8′→(2,6),(3,5),(4,4)sum ' 8 ' \rightarrow(2,6),(3,5),(4,4)\begin{aligned} & (5,3),(6,2) \Rightarrow P(B)=\frac{5}{36} \\ & \begin{aligned} P(\bar{A})=\frac{32}{36} & , P(\bar{B})=\frac{31}{36}\end{aligned}\\ &P(A wins )=P(A)+P(Aˉ)P(Bˉ)P(A)++P(Aˉ)P(Bˉ)P(Aˉ)P(Bˉ)P(A)+…=P(A)1−P(Aˉ)P(Bˉ)=919\begin{aligned} P(A \text{ wins })= & P(A)+P(\bar{A}) P(\bar{B}) P(A)+ \\ & +P(\bar{A}) P(\bar{B}) P(\bar{A}) P(\bar{B}) P(A)+\ldots \\ = & \frac{P(A)}{1-P(\bar{A}) P(\bar{B})}=\frac{9}{19}\end{aligned}\end{aligned}
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