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JEE Main 20241 FebruaryEvening Shift
Exam
JEE Main
Year
2024
Date
1 February
Shift
Evening Shift
Subject
Mathematics
Chapter
Probability

JEE Main 2024 · 1 February · Evening Shift · Mathematics · Probability

Let Ajay will not appear in JEE exam with probability p = (2)/(7),...

Let Ajay will not appear in JEE exam with probability p=27,p = \dfrac{2}{7}, while both Ajay and Vijay will appear in the exam with probability q=15q = \dfrac{1}{5}. Then the probability, that Ajay will appear in the exam and Vijay will not appear is:

Options

  1. A935\dfrac{9}{35}
  2. B1835\dfrac{18}{35}
  3. C2435\dfrac{24}{35}
  4. D335\dfrac{3}{35}

Correct answer

B. 1835\dfrac{18}{35}

Step-by-step solution

The probability that Ajay will not appear in exam is, P(A′)=p=27P\left({A}^{'}\right) = p = \dfrac{2}{7}.

⇒P(A)=57⇒ P\left(A\right) = \dfrac{5}{7}

The probability that Ajay and Vijay will appear in exam is, P(A∩V)=q=15P\left(A \cap V\right) = q = \dfrac{1}{5}.

⇒P(A)×P(V)=15⇒ P\left(A\right) \times P\left(V\right) = \dfrac{1}{5}

⇒P(V)=15×75⇒ P\left(V\right) = \dfrac{1}{5} \times \dfrac{7}{5}

⇒P(V)=725⇒ P\left(V\right) = \dfrac{7}{25}

The probability that Ajay will appear and Vijay will not appear in the exam is,

⇒P(A∩V′)=57×1825⇒ P\left(A \cap {V}^{'}\right) = \dfrac{5}{7} \times \dfrac{18}{25}

⇒P(A∩V′)=1835⇒ P\left(A \cap {V}^{'}\right) = \dfrac{18}{35}

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