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JEE Main 202126 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Evening Shift
Subject
Mathematics
Chapter
Probability

JEE Main 2021 · 26 August · Evening Shift · Mathematics · Probability

A fair die is tossed until six is obtained on it. Let X be the...

A fair die is tossed until six is obtained on it. Let XX be the number of required tosses, then the conditional probability P(X⩾5∣X>2)P ( X ⩾ 5 ∣ X > 2 ) is :

Options

  1. A2536\dfrac{25}{36}
  2. B56\dfrac{5}{6}
  3. C1136\dfrac{11}{36}
  4. D125216\dfrac{125}{216}

Correct answer

A. 2536\dfrac{25}{36}

Step-by-step solution

P(x≥5x>2)=P(x≥5∩x>2)P(x>2)P\left(\dfrac{x \ge 5}{x > 2}\right) = \dfrac{P ( x \ge 5 \cap x > 2 )}{P ( x > 2 )}

=(56)416+(56)516+.......∞(56)2⋅16+(56)316+……….∞= \dfrac{{\left(\dfrac{5}{6}\right)}^{4}\dfrac{1}{6} + {\left(\dfrac{5}{6}\right)}^{5}\dfrac{1}{6} + . . . . . . . \infty}{{\left(\dfrac{5}{6}\right)}^{2} \cdot \dfrac{1}{6} + {\left(\dfrac{5}{6}\right)}^{3}\dfrac{1}{6} + \ldots \ldots \ldots . \infty}

=(56)4⋅161−56(56)2161−56=(56)2=2536= \dfrac{\dfrac{{\left(\dfrac{5}{6}\right)}^{4} \cdot \dfrac{1}{6}}{1 - \dfrac{5}{6}}}{\dfrac{{\left(\dfrac{5}{6}\right)}^{2}\dfrac{1}{6}}{1 - \dfrac{5}{6}}} = {\left(\dfrac{5}{6}\right)}^{2} = \dfrac{25}{36}

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