Two dices are rolled. If both dices have six faces numbered 1 , 2 , 3 , 5 , 7 and 11 , then the probability that the sum of the numbers on the top faces is less than or equal to 8 is:

Step-by-step solution

n S = 36 The possible ordered pairs are 1 , 1 ,   1 , 2 ,   1 , 3 ,   1 , 5 ,   1 , 7 , 2 , 1 ,   2 , 2 ,   2 , 3 ,   2 , 5 ,   3 , 1 ,   3 , 2 ,   3 , 3 ,   3 , 5 ,   5 , 1 5 , 2 , 5 , 3 , 7 , 1 n E = 5 + 4 + 4 + 3 + 1 = 17 So, P E = 17 36