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JEE Main 20257 AprilMorning Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Morning Shift
Subject
Mathematics
Chapter
Quadratic Equation

JEE Main 2025 · 7 April · Morning Shift · Mathematics · Quadratic Equation

Let the set of all values of p ∈ ℝ , for which both the roots of...

Let the set of all values of p∈R\mathrm{p} \in \mathbb{R}, for which both the roots of the equation x2−(p+2)x+(2p+9)=0x^2-(p+2) x+(2 p+9)=0 are negative real numbers, be the interval (α,β](\alpha, \beta]. Then β−2α\beta-2 \alpha is equal toLet the set of all values of p ∈ ℝ , for which both the roots of the equation x^2-(p+2) x+(2 p+9)=0 are negative real

Options

  1. A0
  2. B9
  3. C5
  4. D20

Correct answer

C. 5

Step-by-step solution

Using location of roots :
Let the set of all values of p ∈ ℝ , for which both the roots of the equation x^2-(p+2) x+(2 p+9)=0 are negative real
(i) D≥0\mathrm{D} \geq 0
(ii) −b2a<0\frac{-\mathrm{b}}{2 \mathrm{a}} \lt 0
(iii) a. f(0)>0\mathrm{f}(0) \gt 0
<br/>(p+2)2−4(2p+9)≥0(p+4)(p−8)≥0p+2<02p+9>0<br/>\begin{aligned}<br/>& (p+2)^2-4(2 p+9) \geq 0 \\ & (p+4)(p-8) \geq 0 \quad p+2 \lt 0 \quad 2 p+9 \gt 0<br/>\end{aligned}
Intersection p∈(−92,−4]p \in\left(-\frac{9}{2},-4\right]
∴β−2α=−4+9=5\therefore \beta-2 \alpha=-4+9=5
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