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JEE Main 20248 AprilEvening Shift
Exam
JEE Main
Year
2024
Date
8 April
Shift
Evening Shift
Subject
Mathematics
Chapter
Quadratic Equation

JEE Main 2024 · 8 April · Evening Shift · Mathematics · Quadratic Equation

The number of distinct real roots of the equation...

The number of distinct real roots of the equation ∣x+1∣∣x+3∣−4∣x+2∣+5=0|x+1||x+3|-4|x+2|+5=0, is

Correct answer

2

Step-by-step solution

∣x+1∣∣x+3∣−4∣x+2∣+5=0|x+1||x+3|-4|x+2|+5=0 case-1 x≤−3(x+1)(x+3)+4(x+2)+5=0x2+4x+3+4x+8+5=0x2+8x+16=0(x+4)2=0x=−4\begin{aligned} & x \leq-3 \\ & (x+1)(x+3)+4(x+2)+5=0 \\ & x^2+4 x+3+4 x+8+5=0 \\ & x^2+8 x+16=0 \\ & (x+4)^2=0 \\ & x=-4 \end{aligned} case-2 −3≤x≤−2−x2−4x−3+4x+8+5=0−x2+10=0x=±10\begin{aligned} & -3 \leq x \leq-2 \\ & -x^2-4 x-3+4 x+8+5=0 \\ & -x^2+10=0 \\ & x= \pm \sqrt{10} \end{aligned} case-3 −2≤x≤−1−x2−4x−3−4x−8+5=0−x2−8x−6=0x2+8x+6=0x=−8±2102=−4±10\begin{aligned} & -2 \leq x \leq-1 \\ & -x^2-4 x-3-4 x-8+5=0 \\ & -x^2-8 x-6=0 \\ & x^2+8 x+6=0 \\ & x=\frac{-8 \pm 2 \sqrt{10}}{2}=-4 \pm \sqrt{10} \end{aligned} case-4 x≥−1x2+4x+3−4x−8+5=0x2=0x=0\begin{aligned} & x \geq-1 \\ & x^2+4 x+3-4 x-8+5=0 \\ & x^2=0 \\ & x=0 \end{aligned}
No. of solution =2=2
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