JEE Main20244 Apr 2024Morning ShiftMathematicsQuadratic EquationActual
If 2 and 6 are the roots of the equation a x^2+b x+1=0 , then the quadratic equation, whose roots are 1 2 a+b and 1 6 a+b , is :
Options
- A2 x^2+11 x+12=0
- Bx^2+8 x+12=0
- C4 x^2+14 x+12=0
- Dx^2+10 x+16=0
Correct answer
B. x^2+8 x+12=0
Step-by-step solution
aligned & Sum =8=- b a & Product =12= 1 a a= 1 12 & b=- 2 3 & 2 a+b= 2 12 - 2 3 =- 1 2 & 6 a+b= 6 12 - 2 3 =- 1 6 & sum =-8 & P=12 & x^2+8 x+12=0 aligned