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JEE Main 202431 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
31 January
Shift
Evening Shift
Subject
Mathematics
Chapter
Quadratic Equation

JEE Main 2024 · 31 January · Evening Shift · Mathematics · Quadratic Equation

The number of solutions, of the equation e ^ x - 2 e ^ - x = 2 is

The number of solutions, of the equation esin⁡x−2e−sin⁡x=2{e}^{\sin x} - 2{e}^{- \sin x} = 2 is

Options

  1. A22
  2. Bmore than 22
  3. C11
  4. D00

Correct answer

D. 00

Step-by-step solution

Let, esin⁡x=t{e}^{\sin x} = t

⇒t−2t=2⇒ t - \dfrac{2}{t} = 2

⇒t2−2t−2=0⇒ {t}^{2} - 2t - 2 = 0

⇒t2−2t+1=3⇒ {t}^{2} - 2t + 1 = 3

⇒(t−1)2=3⇒ {\left(t - 1\right)}^{2} = 3

⇒t=1±3⇒ t = 1 \pm \sqrt{3}

⇒t≈2.73,−0.73(not possible)⇒ t \approx 2 . 73, - 0 . 73\left(\text{not possible}\right)

⇒t≈2.73⇒ t \approx 2 . 73

⇒esin⁡x≈2.73⇒ {e}^{\sin x} \approx 2 . 73

⇒sin⁡x≈log⁡e(2.73)⇒ \sin x \approx \log_{e}\left(2 . 73\right)

⇒sin⁡x>1→Not possible⇒ \sin x > 1 \to \text{Not possible}

So no solutions will be possible for the given equation.

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