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JEE Main 202126 AugustEvening Shift
Exam
JEE Main
Year
2021
Date
26 August
Shift
Evening Shift
Subject
Mathematics
Chapter
Quadratic Equation

JEE Main 2021 · 26 August · Evening Shift · Mathematics · Quadratic Equation

Let λ ≠ 0 be in R . If α and β are the roots of the equation x ^ 2...

Let λ≠0\lambda \ne 0 be in R.R . If α\alpha and β\beta are the roots of the equation x2−x+2λ=0,{x}^{2} - x + 2\lambda = 0, and α\alpha and γ\gamma are the roots of the equation 3x2−10x+27λ=0,3{x}^{2} - 10x + 27\lambda = 0, then βγλ\dfrac{\beta\gamma}{\lambda} is equal to ________.

Correct answer

0

Step-by-step solution

α+β=1...(i)\alpha + \beta = 1 . . . \left(i\right)

αβ=2λ...(ii)\alpha\beta = 2\lambda . . . \left(ii\right)
α+γ=103...(iii)\alpha + \gamma = \dfrac{10}{3} . . . \left(iii\right)
αγ=9λ...(iv)\alpha\gamma = 9\lambda . . . \left(iv\right)
from \left(iv\right) \text{ and } \left(ii\right)<br/><br />\dfrac{\gamma}{\beta} = \dfrac{9}{2} . . . (v)\left(v\right)

from \left(iii\right) - (i)\left(i\right)

γ−β=103−1=73...(vi)\gamma - \beta = \dfrac{10}{3} - 1 = \dfrac{7}{3} . . . \left(vi\right)

from \left(v\right)and(vi)and \left(vi\right)

β=23,γ=3\beta = \dfrac{2}{3}, \gamma = 3
from \left(i\right)\alpha = 1 - \beta = 1 - \dfrac{2}{3} = \dfrac{1}{3}<br/>from(ii)λ=αβ2=13×232=19<br />from \left(ii\right)\lambda = \dfrac{\alpha\beta}{2} = \dfrac{\dfrac{1}{3} \times \dfrac{2}{3}}{2} = \dfrac{1}{9}
So βγλ=23×319=18\dfrac{\beta\gamma}{\lambda} = \dfrac{\dfrac{2}{3} \times 3}{\dfrac{1}{9}} = 18

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