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The value of k for which the equation (K-2) x^2+8 x+K+4=0 has both roots real, distinct and negative is

Options

  1. A6
  2. B3
  3. C4
  4. D1

Correct answer

B. 3

Step-by-step solution

(K-2) x^2+8 x+K+4=0 If real roots then, aligned & 8^2-4(K-2)(K+4)>0 & K^2+2 K-8 0 K>-4 & Also, K-2 K+4 >0 K>2 aligned Roots are real so, -6 2 , so 1 is also not correct value of K . K=3

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