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JEE Main 2009
Exam
JEE Main
Year
2009
Subject
Mathematics
Chapter
Quadratic Equation

JEE Main 2009 · Mathematics · Quadratic Equation

If the roots of the equation b x^2+c x+a=0 be imaginary, then for...

If the roots of the equation bx2+cx+a=0b x^2+c x+a=0 be imaginary, then for all real values of xx, the expression 3b2x2+6bcx+2c23 b^2 x^2+6 b c x+2 c^2 is

Options

  1. Agreater than 4ab4 a b
  2. Bless than 4ab4 a b
  3. Cgreater than −4ab-4 a b
  4. Dless than - 4ab

Correct answer

C. greater than −4ab-4 a b

Step-by-step solution

b x²+c x+a=0 Roots are imaginary ⇒c2−4ab<0⇒c2<4ab⇒−c2>−4ab3b2x2+6bcx+2c2\Rightarrow c^2-4 a b \lt 0 \Rightarrow c^2 \lt 4 a b \Rightarrow-c^2 \gt -4 a b3 b^2 x^2+6 b c x+2 c^2 since 3b2>03 b^2 \gt 0 Given expression has minimum value Minimum value =4(3b2)(2c2)−36b2c24(3b2)=−12b2c212b2=−c2>−4ab=\frac{4\left(3 b^2\right)\left(2 c^2\right)-36 b^2 c^2}{4\left(3 b^2\right)}=-\frac{12 b^2 c^2}{12 b^2}=-c^2 \gt -4 a b.
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