JEE Main2007MathematicsQuadratic EquationActual
If the difference between the roots of the equation x^2+a x+1=0 is less than 5 , then the set of possible values of a is
Options
- A(-3,3)
- B(-3, )
- C(3, )
- D(- ,-3)
Correct answer
A. (-3,3)
Step-by-step solution
x^2+a x+1=0 + =-a =1| - |= ( + )^2-4 | - |= a^2-4 a^2-4 < 5 a^2-4 < 5a^2-9 < 0a (-3,3) .