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The value of ' a ' for which one root of the quadratic equation (a^2-5 a+3 ) x^3+(3 a-1) x+2=0 is twice as large as the other is

Options

  1. A- 1 3
  2. B2 3
  3. C- 2 3
  4. D1 3

Correct answer

B. 2 3

Step-by-step solution

3 = 1-3 a a^2-5 a+3 & 2 ^2= 2 a^2-5 a+3 2 [ 1 9 (1-3 a)^2 (a^2-5 a+3 )^2 ]= 2 a^2-5 a+3 (1-3 a)^2 (a^2-5 a+3 ) =9 or 9 a^2-6 a+1=9 a^2-45 a+27 or 39 a=26 or a= 2 3

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